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sfboarbuster
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This is how it would break down, say B is the dominant gene for black nose, and say p is recessive gene for pink noses. You would need both recessive genes from the parents to have a pink nose
Both parents carry recessive gene
Bp X Bp = BB- black nose
Bp- black nose
Bp- black nose
pp- pink nose
One parent carries recessive gene
BB X Bp = BB- Black
BB- Black BB does not carry gene for pink nose, you cannot breed anything to him and get a pink nose
Bp- Black
Bp- Black Bp is a carrier for recessive gene
pp X Bp = Bp
Bp 1/2 black
pp
pp 1/2 pink
BB X pp = Bp
Bp
Bp
Bp Whole litter would have black noses, but would all be carriers of gene
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Logged
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John Esker
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