Message #247185

[sfboarbuster]

This is how it would break down, say B is the dominant gene for black nose, and say p is recessive gene for pink noses. You would need both recessive genes from the parents to have a pink nose

Both parents carry recessive gene
Bp X Bp = BB- black nose
              Bp- black nose
              Bp- black nose
              pp- pink nose

One parent carries recessive gene
BB X Bp = BB- Black
              BB- Black   BB does not carry gene for pink nose, you cannot breed anything to him and get a pink nose
              Bp- Black  
              Bp- Black   Bp is a carrier for recessive gene

pp X Bp = Bp
              Bp     1/2 black
              pp
              pp     1/2 pink

BB X pp = Bp
              Bp
              Bp
              Bp     Whole litter would have black noses, but would all be carriers of gene